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Question ID: 1212

During a manual approach, the aeroplane is subjected to windshear with an increasing head wind

In the absence of a pilot action, the aeroplane

1- flies above the intended approach path
2- flies below the intended approach path
3- has an increasing true airspeed
4- has a decreasing true airspeed

The combination of correct statements is?

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A

1, 4.

B

2, 3.

C

2, 4.

D

1, 3.

Explanation

An increasing headwind would cause a gain in energy for the aircraft. This would lead to:
Flying above the intended approach path
An increasing true airspeed

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Question ID: 1209

You are planning a leg from Bangor (North wales) N53°13'23' W004°08'20' to White churc N52°'58'03 W002°41'00'

What is the maximum altitude of the listed you could fly?

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A

FL55

B

3000feet

C

2700Feet

D

4500feet

Explanation

We have some class A airspace we need to consider between the 2, there is some airspace that is FL55 and the section next to it is 4,500 feet

Important tip - FL55 is the lowest section on one of the airways, on a day where the pressure is let's say 980 , if we are flying at 4,500feet our flight level is actually FL63 - so even though we are at 4,500 feet we would be infringing the class a airspace, so remember to think about this when you are flying around on your PPL

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Question ID: 1207

You are planning to fly from Harrogate N53°95'32 W°001 32'01' to Lancaster N54°02'34' W002°48'13' and then route south to Blackpool

What is your total track distance?

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A

63NM

B

45NM

C

39NM

D

55NM

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Question ID: 1206

You are planning to fly from Harrogate N53°95'32 W°001 32'01' to Lancaster N54°02'34' W002°48'13'

What is your track distance?

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A

45KM

B

83KM

C

31KM

D

109KM

Explanation

All answers are in KM, make sure you check the units

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Question ID: 1205

You are planning to fly from Harrogate N53°95'32 W°001 32'01' to Lancaster N54°02'34' W002°48'13'

What is your track distance?

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A

31NM

B

45NM

C

83NM

D

109NM

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Question ID: 1204

You are planning to fly a leg from Penrith N54°39'49 W002°44'56' to Kendal N54° 19' 36' W002°44'26'

What is your Track?

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A

001°True

B

338° True

C

179°True

D

195° True

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Question ID: 1202

You are planning to fly a leg from Penrith N54°39'49 to Whitehaven W002°44'56'

What is your track?

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A

257°True

B

280° True

C

090° True

D

077°True

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Question ID: 1199

Before refuelling an aeroplane has a weight of 1335 lb and the total moments are 150000 in .lb aft of the datum.

390 lbs of fuel is loaded, with an effective arm of 12 inches aft of the datum.

What will the aeroplane CG position now be?

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A

96.4 inc aft of datum

B

78.4 inc aft of datum

C

92.10 inc aft of datum

D

89.66 inc aft of datum

Explanation

150,000 /1335= 115.38 before the fuel

Add the fuel in -
390 at 12 inches = 4680

150,000 + 4680 = 154680

154680/ the new total weight (1335 +390) = 89.66

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Question ID: 1197

Before refuelling an aeroplane has a weight of 1335 lb and the total moments are 154000 in .lb aft of the datum.

390 lbs of fuel is loaded, with an effective arm of 109 inches aft of the datum.

What will the aeroplane CG position now be?

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A

113.4 inc aft of datum

B

96.4 inc aft of datum

C

78.4 inc aft of datum

D

113.92 inc aft of datum

Explanation

154,000 /1335= 115.35 before the fuel

Add the fuel in -
390 at 109 inches = 42510

154,000 + 42510 = 196,510

196,510/ the new total weight (1335 +390) = 113.92

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Question ID: 1193

Using the attached graph

What will our fuel remaining be at Dover?

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A

38.5

B

41.25

C

40.00

D

42.50

Explanation

For this, we must calculate our fuel burn between Leeds to Oxford using the values we already have

Our actual fuel used between the 2 points was 3.5 in 20 minutes, this means our fuel burn is 10.5 Per hour

There are 20 minutes to Dover , so we must divide 20 minutes (20/60) X fuel burn of 10.5 to get an estimated usage of fuel, and then subtract if from the 42 fuel we had at Oxford

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Question ID: 1191

You are on the approach for Sion Airport (LSGS) on an initial glide slope of 6 degrees, what is the % gradient of the descend?

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Answer:

Correct answer : 11

Explanation

Tan(6) x 100 = 10.51%

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Question ID: 1190

Runway 02 has a threshold elevation of 230 ft and runway 20 has a threshold elevation of 260ft. If the TORA is 1200m calculate the slope of runway 02:

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A

1.56% up

B

0.76% up

C

1.56% down

D

0.76% down

Explanation

Runway Slope % = Runway difference elevation / Length of runway X 100

Runway = 1200M which is 3936 feet (Get everything into the same unit)

The slope of runway = (260-230 = 30 / 3936 ) X 100 = 0.76%

Runway 02 has the slope up, as it has a lower threshold elevation

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Question ID: 1186

Using the graph, and given the following parameters, what is the loaded Centre of Gravity (CG) of this aircraft? BEM 1200 kg Moment 3.00 Front pax 200 kg Cargo on the floor 50 kg Fuel 250 kg

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A

3.03 m

B

2.97 m

C

2.99 m

D

3.00 m

Explanation

Plot across from the BEM 1200kg to the CG position 3.0

From here, plot vertically into the trim part and adjust for the traffic load

Finally, drop back down vertically and read the new Cg where it intercepts the new total mass of 2150kg

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Question ID: 1185

For a given aeroplane mass, a more aft CG position will

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A

increase the take-off distance and reduce the take-off climb performance.

B

decrease the take-off distance and reduce the take-off climb performance.

C

increase the take-off distance and improve the take-off climb performance.

D

decrease the take-off distance and improve the take-off climb performance.

Explanation

With the Cg moving aft, the aircraft effectively becomes lighter as there is less requirement for downforce from the tail

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Question ID: 1179

Calculate the aircraft’s CG position given the following weighing data.

Mass on nose wheel: 285 kg

Mass on left main wheels: 1465 kg

Mass on right main wheels: 1395 kg

Distance between the nose and main wheels: 7 ft 8 in

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A

18.3 in forward of the main gear.

B

83.7 in aft of the nose wheel.

C

9.2 in forward of the main gear.

D

7.1 ft aft of the nose wheel.

Explanation

Use the main gear as the datum.

Arm = 7ft, 8in. (92 inches)
Arm Moment
Nose wheel mass: 285 x 92 -26220
Left wheel mass: 1465
Right wheel mass: 1395

Total Mass: 3145 -26220

CofG: -26220/3145 = -8.34inch

Look at the possible answers. 83.7inches works out at 6.97ft + 0.834 = 7ft 8in

Explanation Provided by Ed

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Question ID: 1178

Calculate the aircraft CG position given the following weighing data.

Mass on nose wheel: 285 kg
Mass on left main wheels: 1465 kg
Mass on right main wheels: 1395 kg
Distance between the nose and main wheels: 7 ft 8 in

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A

18.3 in forward of the main gear.

B

7.1 ft aft of the nose wheel.

C

83.7 in aft of the nose wheel.

D

9.2 in forward of the main gear.

Explanation

Refer to image.

Use nosewheel as the datum.
Now draw a weight-moment-arm table as in the image.

You will need to convert the 7ft 8in into inches = 92inches
Find the CoG = Total Moment/Total Weight = 263120/3145 = 83.66kgin

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Question ID: 1175

In the ATS flight plan Item 10 (equipment), the letter to indicate the carriage of a serviceable transponder ? mode A (4 digits ? 4096 codes) and mode C, is

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A

P

B

A

C

B

D

C

Explanation

Mode A with mode C is classed as Mode C in the item 10 of the ATS flight plan. Also can be asked as what is put in with A and altitude reporting capability.

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Question ID: 1174

Which letter is used in ITEM 9 NUMBER of an ICAO ATS Flight Plan to indicate the wake turbulence category of an aircraft with a Maximum Certificated Take-Off Mass of 6000 kg?

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A

M

B

A

C

H

D

L

Explanation

6000kg falls in to the Light category. If you can't remember the break down there is a table in the ATC section of the Jep.

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Question ID: 1173

When completing Item 9 of the ATS flight plan, if there is no appropriate aircraft designator, the following should be entered

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A

the most descriptive abbreviation

B

“NONE”

C

“XXXX” followed by an entry in Item 18

D

“ZZZZ” followed by an entry in Item 18

Explanation

ZZZZ is entered in. The formalities of filling in an ATC flight plan can be found in the ATC section of the Jep. The more you learn the more time it will save in an exam.

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Question ID: 1172

in ATC Flight plan item 15, speed of 120 Kts will be entered

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A

K0120

B

N0120

C

120KT

D

N120

Explanation

Refer to the jeppesen manual, this is all in there so you dont have to learn all this off by heart

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